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Proof of x ^n algebraically Given (ab) ^n = (n, 0) a ^n b ^0 (n, 1) a ^(n1) b ^1 (n, 2) a ^(n2) b ^2 (n, n) a ^0 b ^n Here (n,k) is the binaryAbrahamŽAo€Xás à Àrcha'©'@•`m"PeÍori" ‹i"xgr†¨• flict'Éterio'0' •àvŽ¡"ó º•°s" d— u ésŒH‹‚"Pve ˜ ¡‰O‰O‰O‰O‰H7‰O6‰O‰O‰O‰O‰O>16‰O>Ù Ú,œÛŽJŽ8 1›H™ês›¡'Àd™Rl àn€0ó–ð'ažÑ 8hag luz, ‹ Šx"؈ ™`orrœp'éamiš completoB✤'"Ó'k› es–aÉÇR h Ôš¡¤íQq ôŽ\ úæ¯÷¥ t™u£ËRQ@ J?ÏZÐÕ {Rž~¢ JQ×¥ I Å J" "v!» `ñNíÖ•²{R Ò€½Ë d ³ ÉëPDA㊲ƒ ƒY³ ¤£ A8æ›» é¬Ù )°gàPNEBÇž( Ub cÉÍ ŠnI¥ ‹ qÊp3Ú›‚0(cÀ ª29â„„ßA½èÅ;iô ©ÏJb QÔ›MFj'Ðôp?h}&1Ncš1VyíêœQN E 9 cKÐñG\ ô§Ò
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Complex Number Wikipedia
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